What is the total capacitance of two 100 uF capacitors connected in series?

When capacitors are connected in series, the total capacitance can be determined using the formula for capacitors in series, which is given by:

1/C_total = 1/C1 + 1/C2 + ... + 1/Cn

In the case of two capacitors, this simplifies to:

1/C_total = 1/C1 + 1/C2

For two 100 µF capacitors, this would be:

1/C_total = 1/100 + 1/100

1/C_total = 1/100 + 1/100 = 2/100

1/C_total = 2/100

Taking the reciprocal to find C_total gives:

C_total = 100/2 = 50 µF

Therefore, the total capacitance of two 100 µF capacitors connected in series is 50 µF. This concept is fundamental in electrical engineering and physics, as it affects how capacitors function in various circuits, specifically in energy storage and voltage stabilization in AC and DC applications.